2x^2+0.7x=61185

Solution for 2x^2+0.7x=61185 equation:

2x^2+0.7x=61185

We move all terms to the left:

2x^2+0.7x-(61185)=0

a = 2; b = 0.7; c = -61185;
Δ = b2-4ac
Δ = 0.72-4·2·(-61185)
Δ = 489480.49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.7)-\sqrt{489480.49}}{2*2}=\frac{-0.7-\sqrt{489480.49}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.7)+\sqrt{489480.49}}{2*2}=\frac{-0.7+\sqrt{489480.49}}{4}
$